Difference between revisions of "CamCASP/Programming/5"
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# More consistent behaviour of aug-cc-pV''n''Z series. |
# More consistent behaviour of aug-cc-pV''n''Z series. |
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# Don't have rotation matrices coded, but these have been derived. |
# Don't have rotation matrices coded, but these have been derived. |
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+ | |||
+ | ===Simple example: 1=== |
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+ | Here's an example that demonstrates the inadequacy of the spherical GTOs. Consider a ''1p1s'' (yes, in this order) main basis and a single occupied orbital. This would be the ''px'' orbital. The space the auxiliary basis needs to span is ''1p1s x 1p1s'' = ''1s1p1d''. So let us construct this auxiliary basis and perform the DF. Here's the question: '''Can the density be exactly fitted using this auxiliary basis?''' |
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+ | |||
+ | The answer depends on which basis type is used for the auxiliary basis. |
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+ | |||
+ | * Cartesian: The auxiliary basis consists of the following combinations: |
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+ | <math> |
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+ | s \ \ x \ \ y \ \ z \ \ x^2 \ \ xy \ \ xz \ \ y^2 \ \ yz \ \ z^2 |
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+ | </math> |
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+ | |||
+ | So the density, <math>x^2</math>, can be exactly described. |
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+ | |||
+ | * Spherical: Now the auxiliary basis consists of the functions: |
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+ | <math> |
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+ | s x y z |
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+ | </math> |
Revision as of 15:47, 12 May 2009
CamCASP => Programming => Auxiliary basis sets
Spherical versus Cartesian GTOs
- What are the advantages of the two basis types: Spherical and Cartesian?
- Which one results in more accurate energies and why?
Spherical GTOs:
- Smaller in size
- More well-defined set of linear equations during DF
- Lower accuracy.
- Seemingly erratic behaviour in aug-cc-pVnZ series.
- Rotations made easy as we have the Wigner rotation matrices.
Cartesian GTOs:
- Larger in size
- DF equations seem OK.
- Higher accuracy of energies
- More consistent behaviour of aug-cc-pVnZ series.
- Don't have rotation matrices coded, but these have been derived.
Simple example: 1
Here's an example that demonstrates the inadequacy of the spherical GTOs. Consider a 1p1s (yes, in this order) main basis and a single occupied orbital. This would be the px orbital. The space the auxiliary basis needs to span is 1p1s x 1p1s = 1s1p1d. So let us construct this auxiliary basis and perform the DF. Here's the question: Can the density be exactly fitted using this auxiliary basis?
The answer depends on which basis type is used for the auxiliary basis.
- Cartesian: The auxiliary basis consists of the following combinations:
<math>
s \ \ x \ \ y \ \ z \ \ x^2 \ \ xy \ \ xz \ \ y^2 \ \ yz \ \ z^2
</math>
So the density, <math>x^2</math>, can be exactly described.
- Spherical: Now the auxiliary basis consists of the functions:
<math>
s x y z
</math>